Optimal. Leaf size=134 \[ -\frac{a^2 (5 A+2 B) \cos ^3(c+d x)}{12 d}-\frac{(5 A+2 B) \cos ^3(c+d x) \left (a^2 \sin (c+d x)+a^2\right )}{20 d}+\frac{a^2 (5 A+2 B) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} a^2 x (5 A+2 B)-\frac{B \cos ^3(c+d x) (a \sin (c+d x)+a)^2}{5 d} \]
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Rubi [A] time = 0.16846, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.161, Rules used = {2860, 2678, 2669, 2635, 8} \[ -\frac{a^2 (5 A+2 B) \cos ^3(c+d x)}{12 d}-\frac{(5 A+2 B) \cos ^3(c+d x) \left (a^2 \sin (c+d x)+a^2\right )}{20 d}+\frac{a^2 (5 A+2 B) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} a^2 x (5 A+2 B)-\frac{B \cos ^3(c+d x) (a \sin (c+d x)+a)^2}{5 d} \]
Antiderivative was successfully verified.
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Rule 2860
Rule 2678
Rule 2669
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int \cos ^2(c+d x) (a+a \sin (c+d x))^2 (A+B \sin (c+d x)) \, dx &=-\frac{B \cos ^3(c+d x) (a+a \sin (c+d x))^2}{5 d}+\frac{1}{5} (5 A+2 B) \int \cos ^2(c+d x) (a+a \sin (c+d x))^2 \, dx\\ &=-\frac{B \cos ^3(c+d x) (a+a \sin (c+d x))^2}{5 d}-\frac{(5 A+2 B) \cos ^3(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{20 d}+\frac{1}{4} (a (5 A+2 B)) \int \cos ^2(c+d x) (a+a \sin (c+d x)) \, dx\\ &=-\frac{a^2 (5 A+2 B) \cos ^3(c+d x)}{12 d}-\frac{B \cos ^3(c+d x) (a+a \sin (c+d x))^2}{5 d}-\frac{(5 A+2 B) \cos ^3(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{20 d}+\frac{1}{4} \left (a^2 (5 A+2 B)\right ) \int \cos ^2(c+d x) \, dx\\ &=-\frac{a^2 (5 A+2 B) \cos ^3(c+d x)}{12 d}+\frac{a^2 (5 A+2 B) \cos (c+d x) \sin (c+d x)}{8 d}-\frac{B \cos ^3(c+d x) (a+a \sin (c+d x))^2}{5 d}-\frac{(5 A+2 B) \cos ^3(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{20 d}+\frac{1}{8} \left (a^2 (5 A+2 B)\right ) \int 1 \, dx\\ &=\frac{1}{8} a^2 (5 A+2 B) x-\frac{a^2 (5 A+2 B) \cos ^3(c+d x)}{12 d}+\frac{a^2 (5 A+2 B) \cos (c+d x) \sin (c+d x)}{8 d}-\frac{B \cos ^3(c+d x) (a+a \sin (c+d x))^2}{5 d}-\frac{(5 A+2 B) \cos ^3(c+d x) \left (a^2+a^2 \sin (c+d x)\right )}{20 d}\\ \end{align*}
Mathematica [A] time = 0.954653, size = 133, normalized size = 0.99 \[ -\frac{a^2 \cos (c+d x) \left (8 (10 A+7 B) \cos (2 (c+d x))+\frac{60 (5 A+2 B) \sin ^{-1}\left (\frac{\sqrt{1-\sin (c+d x)}}{\sqrt{2}}\right )}{\sqrt{\cos ^2(c+d x)}}-135 A \sin (c+d x)+15 A \sin (3 (c+d x))+80 A-30 B \sin (c+d x)+30 B \sin (3 (c+d x))-6 B \cos (4 (c+d x))+62 B\right )}{240 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.064, size = 182, normalized size = 1.4 \begin{align*}{\frac{1}{d} \left ({a}^{2}A \left ( -{\frac{ \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{4}}+{\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{8}}+{\frac{dx}{8}}+{\frac{c}{8}} \right ) +B{a}^{2} \left ( -{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{5}}-{\frac{2\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{15}} \right ) -{\frac{2\,{a}^{2}A \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{3}}+2\,B{a}^{2} \left ( -1/4\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) +1/8\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) +1/8\,dx+c/8 \right ) +{a}^{2}A \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) -{\frac{B{a}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{3}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.02022, size = 181, normalized size = 1.35 \begin{align*} -\frac{320 \, A a^{2} \cos \left (d x + c\right )^{3} + 160 \, B a^{2} \cos \left (d x + c\right )^{3} - 15 \,{\left (4 \, d x + 4 \, c - \sin \left (4 \, d x + 4 \, c\right )\right )} A a^{2} - 120 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} A a^{2} - 32 \,{\left (3 \, \cos \left (d x + c\right )^{5} - 5 \, \cos \left (d x + c\right )^{3}\right )} B a^{2} - 30 \,{\left (4 \, d x + 4 \, c - \sin \left (4 \, d x + 4 \, c\right )\right )} B a^{2}}{480 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.99813, size = 235, normalized size = 1.75 \begin{align*} \frac{24 \, B a^{2} \cos \left (d x + c\right )^{5} - 80 \,{\left (A + B\right )} a^{2} \cos \left (d x + c\right )^{3} + 15 \,{\left (5 \, A + 2 \, B\right )} a^{2} d x - 15 \,{\left (2 \,{\left (A + 2 \, B\right )} a^{2} \cos \left (d x + c\right )^{3} -{\left (5 \, A + 2 \, B\right )} a^{2} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{120 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.05206, size = 371, normalized size = 2.77 \begin{align*} \begin{cases} \frac{A a^{2} x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{A a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{A a^{2} x \sin ^{2}{\left (c + d x \right )}}{2} + \frac{A a^{2} x \cos ^{4}{\left (c + d x \right )}}{8} + \frac{A a^{2} x \cos ^{2}{\left (c + d x \right )}}{2} + \frac{A a^{2} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} - \frac{A a^{2} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} + \frac{A a^{2} \sin{\left (c + d x \right )} \cos{\left (c + d x \right )}}{2 d} - \frac{2 A a^{2} \cos ^{3}{\left (c + d x \right )}}{3 d} + \frac{B a^{2} x \sin ^{4}{\left (c + d x \right )}}{4} + \frac{B a^{2} x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{2} + \frac{B a^{2} x \cos ^{4}{\left (c + d x \right )}}{4} + \frac{B a^{2} \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{4 d} - \frac{B a^{2} \sin ^{2}{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{3 d} - \frac{B a^{2} \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{4 d} - \frac{2 B a^{2} \cos ^{5}{\left (c + d x \right )}}{15 d} - \frac{B a^{2} \cos ^{3}{\left (c + d x \right )}}{3 d} & \text{for}\: d \neq 0 \\x \left (A + B \sin{\left (c \right )}\right ) \left (a \sin{\left (c \right )} + a\right )^{2} \cos ^{2}{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.32936, size = 176, normalized size = 1.31 \begin{align*} \frac{B a^{2} \cos \left (5 \, d x + 5 \, c\right )}{80 \, d} + \frac{A a^{2} \sin \left (2 \, d x + 2 \, c\right )}{4 \, d} + \frac{1}{8} \,{\left (5 \, A a^{2} + 2 \, B a^{2}\right )} x - \frac{{\left (8 \, A a^{2} + 5 \, B a^{2}\right )} \cos \left (3 \, d x + 3 \, c\right )}{48 \, d} - \frac{{\left (4 \, A a^{2} + 3 \, B a^{2}\right )} \cos \left (d x + c\right )}{8 \, d} - \frac{{\left (A a^{2} + 2 \, B a^{2}\right )} \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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